(10w+3)(w-1)-(2-3w)^2=w^2+5w-7

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Solution for (10w+3)(w-1)-(2-3w)^2=w^2+5w-7 equation: 



(10w+3)(w-1)-(2-3w)^2=w^2+5w-7

We move all terms to the left:

(10w+3)(w-1)-(2-3w)^2-(w^2+5w-7)=0

We add all the numbers together, and all the variables

(10w+3)(w-1)-(-3w+2)^2-(w^2+5w-7)=0

We get rid of parentheses

-w^2+(10w+3)(w-1)-(-3w+2)^2-5w+7=0

We multiply parentheses ..

-w^2+(+10w^2-10w+3w-3)-(-3w+2)^2-5w+7=0

We add all the numbers together, and all the variables

-1w^2+(+10w^2-10w+3w-3)-5w-(-3w+2)^2+7=0

We get rid of parentheses

-1w^2+10w^2-10w+3w-5w-(-3w+2)^2-3+7=0

We add all the numbers together, and all the variables

9w^2-12w-(-3w+2)^2+4=0

We move all terms containing w to the left, all other terms to the right

9w^2-12w-(-3w+2)^2=-4

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